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A(ClH2COONa)^infty = 224 Omega ^(-1)cm^(...

`A_(ClH_2COONa)^infty = 224 Omega ^(-1)cm^(2) g equiv^(-1)`
`A_(NaCl)^infty=38.5Oemga^(-1) cm^(2) g equiv^(-1)`
`(A_(HCl)^infty) = 230Omega^(-1) cm^(2) g equiv ^(-1)`
What is the value of `wedge_(ClCH_(2) COOH)^infty` = ?

A

`288.5ohm^(-1)cm^(2)gm eq^(-1)`

B

`289.5ohm^(-1)ohm^(-1)cm^(2)gmeq^(-1)`

C

`388.8ohm^(-1)cm^(2)gmeq^(-1)`

D

`59.5ohm^(-1)cm^(2)gmeq^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`lambda_(ClCH_(2)COOH)=lambda_(ClCH_(2)COONa)+ lambda_(HCl)-lambda_(NaCl)`
`=(224+203-38.2)ohm^(-1)cm^(2)(g eq^(-1))`
=`388.8ohm^(-1)cm^(2)(g eq^(-1))`
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