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The hydrogen electrode is dipped in a so...

The hydrogen electrode is dipped in a solution of pH =3 at `25^(@)C`. The reduction potential of the electrode would be

A

0.177V

B

0.087V

C

`-0.177V`

D

`0.059V`

Text Solution

Verified by Experts

The correct Answer is:
C
`pH=3`
`therefore [H^(+)]=10^(-3)`
`H^(+)+e^(-)rarr(1)/(2)H_(2)`
`E=E^(@)-(0.059)/(n)"log" (1)/([H^(+)])=0-(0.059)/(1)"log"10^(3)`
` E=-0.177V`
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