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If 3 F of electricity is passed through ...

If 3 F of electricity is passed through the solutions of `AgNO_3`, `CuSO_4` and `AuCl_3`, the molar ratio of the cations deposited at the cathodes will be:

A

`1:1:1`

B

` 1 :2 :3`

C

`3:2 :1`

D

` 6:3:2`

Text Solution

Verified by Experts

The correct Answer is:
D
`Ag^(+)+e^(-)rarrAg`
3F of electricity will produce 3 moles of Ag.
`Cu^(2+)+2e^(-)rarrCu`
3F of electricity will produce 3/2 moles of Cu
`Au^(3+)+3e^(-)rarrAu`
3F of electricity will produce 1 mole of Au `therefore` Molar ratio of
`Ag:Cu:Au`
or `6:3:2`
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