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E(Cu^(+2)//Cu)^(@)=0.34V, E(Zn//Zn^(+2))...

`E_(Cu^(+2)//Cu)^(@)=0.34V, E_(Zn//Zn^(+2))^(@)=0.76V`
A cell formed by the conbination of Cu and Zn
(a) when `CuSO_(4)` is added to `Cu^(+2)` compartment what is the effect on emf of cell
(b) when `NH_(3)` is added to `Cu^(+2)` compartment what is the effect on emf of cell
(c ) When `ZnSO_(4)` is added to `Zn^(+2)` compartment is the effect on emf of cell
(d) When `Zn^(+2)` is diluted what is the effect on emf of cell ?

A

1.10V

B

1.04V

C

1.16V

D

1.07V

Text Solution

Verified by Experts

The correct Answer is:
D
`Zn|Zn^(2+)||Cu^(2+)|Cu`
`Zn+Cu^(2+)+rarrZn^(2+)+Cu`
`E_("cell")^(@)=E_(Cu^(2+)._(//Cu))-E_(Zn^(2+)._(//Zn))^(@)`
`=0.34-(-0.76)=1.10V`
`E_("cell")=E_("cell")^(@)(0.0591)/(2)"log"([Zn^(2+)])/([Cu^(2+)])`
`=1.10V-(0.0591V)/(2)"log"(0.1)/(0.01)`
`=10.7045V`
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