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The standard e.m.f of a cell, involving ...

The standard e.m.f of a cell, involving one electron change is found to be 0.591 V at `25^(@) C`. The equilibrium constant of the reaction is : `(F=96,500C mol^(-1)`: R=8.314 `Jk^(-1)mol^(-1)`

A

`1.0xx10^(1)`

B

`1.0xx10^(30)`

C

`1.0xx10^(10)`

D

`1.0xx10^(5)`

Text Solution

Verified by Experts

The correct Answer is:
C
At 298
`E^(@)=(0.0591)/(n)"log" k_(c)`
`0.591=(0.0591)/(1)"log"K_(c)`
`"log" k_(c)=(0.5910)/(0.0591)`
` "log"k_(c)=10`
`K_(c)=10^(10)`
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