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The limiting molar conductivities overse...

The limiting molar conductivities `overset(o)(wedge)` for NaCl, KBr and KCl are 126, 152 and `150 S cm^(2)mol^(-1)` respectively. The `overset(o)(wedge)` for NaBr is:

A

`128Scm^(2)"mol"^(-1)`

B

`302Scm^(2)"mol"^(-1)`

C

`278S cm^(2)"mol"^(-1)`

D

`176Scm^(2)"mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`^^_(NaBr)^(@)=^^_(NaCl)^(@)+^^_(KBr)^(@)-^^_(KCl)^(@)`
`=126+152-150=128 S cm^(2)"mol"^(-1)`
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