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When a quantity of electricity is passed...

When a quantity of electricity is passed through `(CUSO_(4))` solution, 0.16 g of copper gets deposited. If the same quantity of electricity is passed through acidulated water,then the volume of `(H_2)` liberated at STP will be : [Given , atomic weight of Cu = 64]

A

`4.0cm^(3)`

B

`56cm^(3)`

C

`604cm^(3)`

D

`8.0cm^(3)`

Text Solution

Verified by Experts

The correct Answer is:
B
`("Mass of Cu deposited")/("Volume of" H_("liberated"))=("Eq. wt of Cu")/("Eq. wt. of H")`
`(0.18)/("Mass of" H_(2) "liberated")=(64//2)/(1)`
or mass of `H_(2)` liberated `=(0.16)/(32)g=5xx10^(-3)g`
`therefore` volume of `H_(2)` liberated at STP
`=(22400)/(2)xx5xx10^(-3)cm^( 3)=56cm ^(3)`
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