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The standard electrode potential of the ...

The standard electrode potential of the half cells are given below :
`Zn^(2+)+ 2e^(-) rarr Zn(s), E^(o) = - 7.62 V `
`Fe^(2+) + 2e^(-) rarr Fe(s) , E^(o) = -7 .81 V`
The emf of the cell `Fe^(2+) + Zn rarr Zn^(2+) + Fe` will be :

A

`-0.32V`

B

`-1.20V`

C

`+1.20V`

D

`+0.32V`

Text Solution

Verified by Experts

The correct Answer is:
D
`Fe^(2+)+ZnrarrZn^(2+)+Fe`
`ZnrarrZn^(2+)+2e^(-)`
`ZnrarrZn^(2+)+2e^(-)`
`Fe^(2+)+2e^(-)rarrFe`
`Zn|Zn^(2+)||Fe^(2+)|Fe`
`EMF^(@)=E_(Fe^(2+)//Fe)^(@)-E_(Zn^(2+)//Zn)^(@)`
`=-0.44-(-0.76)`
`=0.76-0.44=+0.32V`
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