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The potential of the cell for the reacti...

The potential of the cell for the reaction, `M(s)+2H^(+) (1M)rightarrow H_(2) (g) (1atm)+M^(2+) (0.1m)`' is 1.500 V. The standard reduction potential for `M^(2+)` / M(s) couple is :

A

0.1470V

B

1.470V

C

`-1.47V`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
The cell is
`M|M^(2+)(0.1M)||H^(+)(M)|H^(+)(M)|H _(2)(1"atm")`
`E_("cell")=E_("cell")^(@)-(0.0591)/(2)"log"[M^(2+)]`
`1.5=E_("cell")^(@)-(0.0591)/(2)"log"(0.1)`
`1.5=E_("cell")^(@)+0.02955`
or `E_("cell")^(@)=E_(2H^(+)//H_(2))^(@)-E_(M^(2+)//M)^(@)`
`therefore 1.47=0-E_(M^(2+)//M)^(@)`
or `E_(M^(2+)//M)^(@)=-1.47V`.
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