Home
Class 12
CHEMISTRY
How many moles of Pt may be deposited on...

How many moles of Pt may be deposited on the cathode when 0.80F of electricity is passed through 1.0M solution of `Pt^(4+)`?

A

1.0mol

B

0.20mol

C

0.4mol

D

0.80mol

Text Solution

Verified by Experts

The correct Answer is:
B

` Pt^(4+)+4e^(-)rarrPt`
4F will deposit Pt =1 mol
`0.1F` will deposit `Pt=(1)/(4)xx0.08` m ole
=0.2 mole.
Promotional Banner

Similar Questions

Explore conceptually related problems

An electric current is passed through silver nitrate solution using silver electrodes. 15.28 g of silver was found to be deposited on catode. What will be the weight of copper deposited on cathode if same amount of electricity is passed through copper sulphate solution using copper electrodes?

How much copper is deposited on the cathode if a current of 3A is passed through aqueous CuSO_(4) solution for 15 minutes?

Name the law or principle to which the following observations conform : (1) When water is added to a 1.0 M aqueous solution of acetic acid, the number of hydrogen ion ( H^+ ) increases. (2) When 9650 coulombs of electricity is passed through a solution of copper sulphate, 3.175 g of copper is deposited on the cathode.(at. wt. of Cu = 63.5). (3) When ammonium chloride is added to a solution of ammonium hydroxide, the concentration of hydroxyl ions decreases.

0.02 equivalent of Ag was deposited in an electrolysis experiment. If same quantity of a electricity is passed through a gold solution, 1.314 g of gold is deposited. Find oxidation state of the gold. (Atomic mass of Au = 197)

How many coulombs of electricity are c onsumed when a 100mA current is passed through a solution of AgNO_(3) for half an hour during an electrolysis experiment?

Calculate the time required to deposit 1.27 g of copper at cathode when a current of 2A was passed through the solution of CuSO_(4) . ("Molar mass of "Cu=63.5g mol^(-1), 1F =96500 C mol^(-1)).

0.169 gram of copper is deposited on the cathode by a current of 32 milliamperes passing for 5 hours through a solution of copper sulphate. Determing the current efficiency. [ Atomic weight of Cu=63.6]

The electrolytic cell, one containing acidified ferrous chlo- ride and another with acidified ferric chloride are connected in series. The ratio of iron deposited at cathodes in the two cells when electricity is passed through the cells will be:

When a quantity of electricity is passed through CuSO_(4) solution, 0.16 g of copper gets deposited. If the same quantity of electricity is passed through acidulated water, then the volume of H_(2) liberated at STP will be : (given atomic weight of Cu=64)

The number of moles of Zn^(2+) ions deposited when a current of 1.5A is passed for 4 hours through a molten solution of a zinc salt. ( Assume current efficiency to be 90%)