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9.65C of electric current is passed thro...

`9.65C` of electric current is passed through fused anhydrous magnesium chloride. The magnesium metal is completely converted into a Grignard reagent. The number of moles of the Grignard reagent obtained is `Axx10^(-5)` then value of `A` is

A

`5xx10^(-4)`

B

`1xx10^(-4)`

C

`5xx10^(-5)`

D

`1xx10^(-5)`

Text Solution

Verified by Experts

The correct Answer is:
C
`Mg^(2+)+2e^(-)rarrMg`
2F,i.e.`2xx96500C` deposit Mg=1mol
`therefore 9.65C` will deposit Mg
`=(1)/(2xx96500)xx9.65=5xx10^(-5)` mol
`RX+MgrarrRMgX`
1 mole of Mg forms G.R.=1mol
`therefore 5xx10^(-5)` mole of Mg will form G.R. `=5xx10^(-5)` mol.
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