The cell potential of a hydrogen electr...

The cell potential of a hydrogen electrode at pH =10

A

0.59V

B

0.00V

C

`-0.59V`

D

`-0.059V`

Verified by Experts

The correct Answer is:

C

`H^(+)+erarr(1)/(2)H_(2)`
`E=E^(@)-(0.0591)/(1)"log"(1)/([H^(+)])=-0.0591xxpH`
`=0-0.0591xx10=-0.591V`.

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