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For the electrochemical cell, M|M^(+)||X...

For the electrochemical cell, `M|M^(+)||X^(-)|X, E^(@)(M^(+)|M|)=0.44V and E^(@)(X|X|^(-))=0.33V`. From this data one can deduce that

A

`M+XrarrM^(+)+X^(-)` is the spontaneous reaction

B

`M^(+)+X^(-)rarrM+X` is the spontaneous reaction

C

`E_("cell")=0.77V`

D

`E_("cell")=-0.77`V.

Text Solution

Verified by Experts

The correct Answer is:
B
`M|M^(+)||X^(-)|X`
The two half cell reactions for the cell are
`MrarrM^(+)+e^(-)`
or `X+e^(-)rarrX^(-)`
`M+XrarrM^(+)+X`
`E_("cell")^(@)=E_(X//X^(-))^(@)-E_(M^(+)//M)`
`=0.33V-0.44V=-0.11V`
As `E_("Cell")^(@)` is negative the reaction involved is non spon taneus. the reverse reaction, howev er, will be spontaneous.
`M^(+)+X^(-)rarrM+X`
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