When a cell is placed in 0.25 M concentrated suger solution, there is no change in it. The concentration of cell sap would be

Options

A. 0.025 M
B. 0.25 M
C. 25 M
D. None of the above

Answer

To determine the concentration of cell sap when a cell is placed in a 0.25 M concentrated sugar solution with no change, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Isotonic Solutions**: When a cell is placed in a solution and there is no change in the cell's size or shape, it indicates that the solution is isotonic to the cell sap. This means that the concentration of solutes outside the cell is equal to the concentration of solutes inside the cell.

2. **Identifying the Concentration of the External Solution**: In this case, the external solution is a 0.25 M sugar solution. Since there is no change in the cell, we can conclude that the concentration of the cell sap must also be 0.25 M.

3. **Conclusion**: Therefore, the concentration of the cell sap is equal to the concentration of the external solution, which is 0.25 M.

4. **Final Answer**: The concentration of the cell sap is 0.25 M.

### Answer: B) 0.25 M

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