A and B cells are contiguous. Cell A has OP=10 atm, TP=7 atm and DPD=3 atm. Cell B has OP=8 atm. TP=3 atm and DPD=5 atm. The result would be

Options

A. No movement of water
B. Equilibrium between the two
C. Movement of water from A to B
D. Movement of water from B to A

Answer

To solve the problem, we need to analyze the osmotic pressure (OP), turgor pressure (TP), and diffusion pressure deficit (DPD) of both cells A and B.

### Step-by-Step Solution:

1. **Understand the Definitions**:
- **Osmotic Pressure (OP)**: The pressure required to prevent the flow of water into a solution by osmosis.
- **Turgor Pressure (TP)**: The pressure exerted by the fluid (usually water) inside the cell against the cell wall.
- **Diffusion Pressure Deficit (DPD)**: The difference between the osmotic pressure of pure water and the osmotic pressure of the solution. It indicates the tendency of water to move into the cell.

2. **Calculate DPD for Both Cells**:
- For Cell A:
- DPD_A = OP_A - TP_A
- DPD_A = 10 atm - 7 atm = 3 atm
- For Cell B:
- DPD_B = OP_B - TP_B
- DPD_B = 8 atm - 3 atm = 5 atm

3. **Compare DPD Values**:
- DPD_A = 3 atm
- DPD_B = 5 atm
- Since DPD_B (5 atm) is greater than DPD_A (3 atm), water will move from Cell B to Cell A.

4. **Conclusion**:
- Water moves from the cell with higher DPD (Cell B) to the cell with lower DPD (Cell A). Therefore, the result is that water will flow from Cell B to Cell A.

### Final Answer:
Water will move from Cell B to Cell A.

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