Water potentials of pure water and its solution are

Options

A. 0 and 1
B. 0 and 0
C. 0 and more than one
D. 0 and less than one .

Answer

To solve the question regarding the water potentials of pure water and its solution, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Water Potential**:
- Water potential (Ψ) is a measure of the potential energy in water, which influences the movement of water in and out of cells.
- It is affected by two main components: solute potential (Ψs) and pressure potential (Ψp).

2. **Water Potential of Pure Water**:
- Pure water has a water potential of 0. This is because it has no solutes dissolved in it, and under standard conditions (no pressure), its solute potential is also 0.
- Therefore, for pure water, Ψ = Ψs + Ψp = 0 + 0 = 0.

3. **Water Potential of a Solution**:
- When a solute is added to water, it forms a solution. The presence of solute particles affects the movement of water molecules, thereby reducing the kinetic energy of the water.
- The solute potential (Ψs) of a solution is always negative because the addition of solute lowers the water potential compared to pure water.

4. **Comparison of Water Potentials**:
- Since the water potential of pure water is 0 and that of a solution (which has solute) is negative, we can conclude that:
- Water potential of pure water (Ψw) = 0
- Water potential of a solution (Ψs) < 0 (negative value)

5. **Conclusion**:
- The water potential of pure water is 0, and the water potential of its solution is less than 0 (negative). Thus, the correct answer is that the water potential of pure water is 0 and that of its solution is less than 0.

### Final Answer:
- Water potential of pure water: 0
- Water potential of its solution: less than 0 (negative)