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X and Y are adjacent living cells. The c...

X and Y are adjacent living cells. The cell X has solute potential `(Psi_(s))` of -9 bars and preesure potential `(Psi_(p))` of bars wherease cell Y has solute potential `(Psi_(s))` of -8 bars and pressure potential `(Psi_(p))` of 5 bars. What will be the direction of water movement between these cells

A

Cell X to cell Y

B

Cell Y to cell X

C

Does not move in any direction

D

Moves in both directions.

Text Solution

AI Generated Solution

The correct Answer is:
To determine the direction of water movement between the two adjacent living cells, X and Y, we need to calculate the water potential for each cell using the formula: \[ \Psi = \Psi_s + \Psi_p \] Where: - \(\Psi\) is the water potential, - \(\Psi_s\) is the solute potential, - \(\Psi_p\) is the pressure potential. ### Step 1: Calculate Water Potential for Cell X Given: - \(\Psi_s\) for Cell X = -9 bars - \(\Psi_p\) for Cell X = 4 bars Using the formula: \[ \Psi_X = \Psi_s + \Psi_p = -9 \text{ bars} + 4 \text{ bars} = -5 \text{ bars} \] ### Step 2: Calculate Water Potential for Cell Y Given: - \(\Psi_s\) for Cell Y = -8 bars - \(\Psi_p\) for Cell Y = 5 bars Using the formula: \[ \Psi_Y = \Psi_s + \Psi_p = -8 \text{ bars} + 5 \text{ bars} = -3 \text{ bars} \] ### Step 3: Compare Water Potentials - Water potential of Cell X (\(\Psi_X\)) = -5 bars - Water potential of Cell Y (\(\Psi_Y\)) = -3 bars ### Step 4: Determine Direction of Water Movement Water moves from an area of higher water potential to an area of lower water potential. In this case: - Cell Y has a higher water potential (-3 bars) compared to Cell X (-5 bars). Thus, the direction of water movement will be from Cell Y to Cell X. ### Final Answer Water will move from Cell Y to Cell X. ---
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Knowledge Check

  • The cell A has an osmotic potential of -20 bars and a pressure potential of +6 bars. What will be its water potential?

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    `Psi_(w)=Psi_(s)+Psi_(rho)`
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    D
    `Psi_(w)=Psi_(s)=Psi_(rho)`
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