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A plant is provided with ideal condition...

A plant is provided with ideal conditions for photosynthesis and supplied with isotope `.^(14)CO_(2)`. When the products of the process are analysed carefully, what would be nature of products

A

Both glucose and oxygen are labelled

B

Only oxygen is labelled but glucose is normal

C

Both glucose and oxygen are normal

D

Only glucose is labelled and oxygen is normal.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the nature of products when a plant is provided with ideal conditions for photosynthesis and supplied with isotope \(^{14}CO_2\), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Photosynthesis**: Photosynthesis is the process by which plants convert carbon dioxide (\(CO_2\)) and water (\(H_2O\)) into glucose (\(C_6H_{12}O_6\)) and oxygen (\(O_2\)) using sunlight and chlorophyll. 2. **Chemical Equation**: The overall equation for photosynthesis can be represented as: \[ 6CO_2 + 12H_2O \xrightarrow{\text{light, chlorophyll}} C_6H_{12}O_6 + 6O_2 \] Here, \(CO_2\) is reduced to form glucose, and \(H_2O\) is oxidized to release oxygen. 3. **Role of Isotope**: When the plant is supplied with \(^{14}CO_2\), the carbon atoms in the carbon dioxide are labeled with the radioactive isotope \(^{14}C\). This means that any carbon that gets incorporated into glucose during photosynthesis will carry the \(^{14}C\) label. 4. **Incorporation of Isotope**: - The \(^{14}C\) from \(^{14}CO_2\) will be incorporated into the glucose molecule during the synthesis. - The oxygen produced as a byproduct comes from the water (\(H_2O\)), not from the carbon dioxide. 5. **Analyzing the Products**: - The glucose produced will contain the \(^{14}C\) isotope, making it a labeled glucose molecule. - The oxygen released will be normal (not labeled) because it originates from the water molecules. 6. **Conclusion**: Based on the above analysis, when the products of photosynthesis are analyzed, the nature of the products will be: - Only glucose is labeled (contains \(^{14}C\)). - Oxygen is normal (not labeled). ### Final Answer: Only glucose is labeled and oxygen is normal. ---
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