How many NADPH and ATP molecules are used in Calvin cycle for production of trioses required for synthesis of 6 surcose molecules

Options

A. 144 NADPH, 216 ATP
B. 288 NADPH, 432 ATP
C. 144 NADPH, 288 ATP
D. 72 NADPH, 108 ATP.

Answer

To determine how many NADPH and ATP molecules are used in the Calvin cycle for the production of trioses required for the synthesis of 6 sucrose molecules, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Basic Requirements for Sucrose Production**:
- Each sucrose molecule is made up of two triose molecules (glyceraldehyde-3-phosphate, G3P).
- Therefore, to produce 6 sucrose molecules, we need to produce \(6 \times 2 = 12\) triose molecules.

2. **Identify the ATP and NADPH Requirements for One Sucrose**:
- From the Calvin cycle, it is known that for the production of one sucrose molecule, the cycle requires:
- 18 ATP
- 12 NADPH

3. **Calculate the Requirements for 12 Trioses**:
- Since 1 sucrose requires 18 ATP and 12 NADPH, for 12 trioses (which corresponds to 6 sucrose):
- ATP required for 12 trioses = \(18 \text{ ATP} \times 6 = 108 \text{ ATP}\)
- NADPH required for 12 trioses = \(12 \text{ NADPH} \times 6 = 72 \text{ NADPH}\)

4. **Final Calculation for 6 Sucrose Molecules**:
- For the synthesis of 6 sucrose molecules, we need to multiply the requirements for one sucrose by 6:
- Total ATP = \(18 \text{ ATP} \times 6 = 108 \text{ ATP}\)
- Total NADPH = \(12 \text{ NADPH} \times 6 = 72 \text{ NADPH}\)

5. **Conclusion**:
- Therefore, for the synthesis of 6 sucrose molecules, a total of **108 ATP** and **72 NADPH** are required.

### Final Answer:
- **NADPH required**: 72
- **ATP required**: 108