Match and choose the true option

Options

A. NaCl-Inorganic micromolecule
B. `H_(2)O`-Organic micromolecule
C. Starch-Organic micromolecule
D. Glucose-inorganic micromolecule

Answer

To solve the question of matching and choosing the true option regarding the classification of molecules, we will follow these steps:

### Step 1: Understand the Definitions
- **Organic Molecules**: These are compounds that contain carbon. Examples include carbohydrates, proteins, lipids, and nucleic acids.
- **Inorganic Molecules**: These do not contain carbon. Examples include salts, minerals, and water.
- **Micromolecules**: These are small molecules, typically monomers or simple compounds with low molecular weight. Examples include monosaccharides, amino acids, and water.
- **Macromolecules**: These are large molecules, typically polymers made up of many monomer units. Examples include starch, proteins, and nucleic acids.

### Step 2: Analyze Each Option
1. **Sodium Chloride (NaCl)**:
- Contains no carbon → Inorganic
- Simple ionic compound → Micromolecule
- **Classification**: Inorganic micromolecule (True)

2. **Water (H2O)**:
- Contains no carbon → Inorganic
- Simple molecule → Micromolecule
- **Classification**: Inorganic micromolecule (True)

3. **Starch**:
- Contains carbon → Organic
- Polymer of glucose → Macromolecule
- **Classification**: Organic macromolecule (False)

4. **Glucose (C6H12O6)**:
- Contains carbon → Organic
- Simple sugar → Micromolecule
- **Classification**: Organic micromolecule (True)

### Step 3: Choose the True Option
From the analysis:
- Sodium Chloride is an inorganic micromolecule (True).
- Water is an inorganic micromolecule (True).
- Starch is an organic macromolecule (False).
- Glucose is an organic micromolecule (True).

The only option that is stated correctly in the question is:
- **Sodium Chloride (NaCl)** is an inorganic micromolecule.

### Conclusion
The correct answer is **Sodium Chloride (NaCl)** as it is classified as an inorganic micromolecule.

---