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The bond present between AMP+P(i)" and "...

The bond present between `AMP+P_(i)" and "ADP+P_(i)` are

A

Phosphoester bonds

B

Phosphoanhydride bonds

C

Phosphodiester bonds

D

Covalent bonds.

Text Solution

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The correct Answer is:
To determine the type of bond present between AMP + Pi (inorganic phosphate) and ADP + Pi, we need to analyze the structure and bonding of these molecules. ### Step-by-Step Solution: 1. **Understanding the Molecules**: - AMP (Adenosine Monophosphate) consists of an adenine base, a ribose sugar, and one phosphate group. - ADP (Adenosine Diphosphate) consists of an adenine base, a ribose sugar, and two phosphate groups. 2. **Formation of ADP from AMP**: - When AMP combines with an inorganic phosphate (Pi), it forms ADP. This reaction can be represented as: \[ AMP + Pi \rightarrow ADP \] 3. **Identifying the Bonds**: - The bond formed between AMP and Pi is a high-energy bond. This is because the addition of a phosphate group to AMP to form ADP involves the release of energy, which is characteristic of high-energy phosphate bonds. 4. **Types of Bonds**: - The bonds in question are specifically known as phosphoanhydride bonds. These are the bonds that link the phosphate groups in ATP, ADP, and AMP. - In ATP, the bonds between the second and third phosphate groups (the terminal phosphates) are also phosphoanhydride bonds and are considered high-energy bonds. 5. **Conclusion**: - Therefore, the bond present between AMP + Pi and ADP + Pi is a **phosphoanhydride bond**. ### Final Answer: The bond present between AMP + Pi and ADP + Pi is a **phosphoanhydride bond**. ---
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