Which biomolecule is correctly charaterised

Options

A. Lecithin - Phoshorylated glyceride found in cell membrane
B. Palmitic Acid - An unsaturated fatty acids with 18 carbon atoms
C. Adenylic Acid - Adenosine with glucose phosphate molecule
D. Alanine Amino Acid - Contains an amino group and an acid group anywhere in the molecule.

Answer

To determine which biomolecule is correctly characterized, we will analyze each of the provided options: lecithin, palmitic acid, adenylic acid, and alanine.

### Step-by-Step Solution:

1. **Analyze Lecithin**:
- Lecithin is described as a phosphorylated glyceride found in the cell membrane.
- It is indeed a major component of phospholipids, which are crucial for forming cell membranes.
- **Conclusion**: Lecithin is correctly characterized.

2. **Analyze Palmitic Acid**:
- Palmitic acid is claimed to be an unsaturated fatty acid with 18 carbon atoms.
- However, palmitic acid is actually a saturated fatty acid with 16 carbon atoms (C16:0).
- **Conclusion**: This characterization is incorrect.

3. **Analyze Adenylic Acid**:
- Adenylic acid is described as adenosine with a glucose phosphate molecule.
- Adenylic acid, also known as adenosine monophosphate (AMP), is a nucleotide and does not contain glucose.
- It is formed from adenosine and a phosphate group.
- **Conclusion**: This characterization is incorrect.

4. **Analyze Alanine**:
- Alanine is described as an amino acid that contains an amino group and an acid group.
- While alanine does contain these groups, the description lacks specificity regarding its structure.
- Alanine is a non-polar amino acid with the formula CH3-CH(NH2)-COOH.
- **Conclusion**: This characterization is not entirely accurate.

### Final Conclusion:
The only biomolecule that is correctly characterized is **Lecithin** (Option A).