Arrange the following compounds in descending order on the basis of number of carbon atoms present in them
(a) Palmitic acid`" "` (b) Serine
(c ) Ribose`" "` (d) Arachidonic
(e ) Glucose

Options

A. d,c,a,b,e
B. b,c,e,a,d
C. d,a,e,c,b
D. c,b,a,d,e.

Answer

To arrange the given compounds in descending order based on the number of carbon atoms present in each, we will first determine the number of carbon atoms in each compound:

1. **Palmitic Acid**: The empirical formula is C16H32O2. This indicates that palmitic acid contains **16 carbon atoms**.

2. **Serine**: The chemical formula is C3H7O3. This means serine contains **3 carbon atoms**.

3. **Ribose**: The formula for ribose is C5H10O5, which indicates that ribose contains **5 carbon atoms**.

4. **Arachidonic Acid**: The formula for arachidonic acid is C20H32O2, meaning it contains **20 carbon atoms**.

5. **Glucose**: The chemical formula for glucose is C6H12O6, which indicates that glucose contains **6 carbon atoms**.

Now, we can summarize the number of carbon atoms in each compound:
- Arachidonic Acid: 20 carbon atoms
- Palmitic Acid: 16 carbon atoms
- Glucose: 6 carbon atoms
- Ribose: 5 carbon atoms
- Serine: 3 carbon atoms

Next, we will arrange these compounds in descending order based on the number of carbon atoms:
1. Arachidonic Acid (20)
2. Palmitic Acid (16)
3. Glucose (6)
4. Ribose (5)
5. Serine (3)

Thus, the final arrangement in descending order of carbon atoms is:
1. Arachidonic Acid
2. Palmitic Acid
3. Glucose
4. Ribose
5. Serine