A white eyed and long winged male Drosophila was crossed to a vestigial winged (recessive) red eyed female .The two characters are linked in this anmla .When a female `F_(1)` was crossed the `F_(2)` generation produced

Options

A. Mostly white eyesd with long wings
B. Mostly red eyed with vestigial wings
C. Mostly white eyed with long wings and red eyed with vestigial wings
D. All white eyed and vertigial winged

Answer

To solve the problem, we need to analyze the genetic cross between the Drosophila (fruit flies) based on the given traits: eye color and wing shape. Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the Genotypes of the Parents
- The male Drosophila has white eyes and long wings. Since white eyes (W) are recessive, we denote his genotype as **W W L L** (homozygous dominant for long wings).
- The female Drosophila has red eyes (w) and vestigial wings (l), which are both recessive traits. Her genotype is **w w l l** (homozygous recessive for both traits).

### Step 2: Determine the Gametes Produced by Each Parent
- The male can produce gametes with the alleles: **W L** (for white eyes and long wings).
- The female can produce gametes with the alleles: **w l** (for red eyes and vestigial wings).

### Step 3: Perform the F1 Cross
When we cross the male and female, we can set up a Punnett square to determine the F1 generation:
- The F1 offspring will all inherit one allele from each parent:
- All offspring will have the genotype **W w L l** (heterozygous for both traits).

### Step 4: Analyze the F1 Generation
The F1 generation will exhibit the dominant traits:
- All will have red eyes (since red is dominant over white).
- All will have long wings (since long is dominant over vestigial).

### Step 5: Cross the F1 Generation to Produce F2
Now, we need to cross two F1 individuals (W w L l x W w L l) to produce the F2 generation.

### Step 6: Set Up the Punnett Square for F2 Generation
We can set up a dihybrid cross for the two traits:
- Possible gametes from F1: **W L, W l, w L, w l**.

Using a 4x4 Punnett square, we would get the following combinations:

| | WL | Wl | wL | wl |
|----------|--------|--------|--------|--------|
| **WL** | WWLL | WWLl | WwLL | WwLl |
| **Wl** | WWLl | WWll | WwLl | Wwll |
| **wL** | WwLL | WwLl | wwLL | wwLl |
| **wl** | WwLl | Wwll | wwLl | wwll |

### Step 7: Count the Phenotypes
From the Punnett square, we can count the phenotypes:
- **Dominant Traits (White eyes and Long wings)**:
- WWLL, WWLl, WwLL, WwLl (total of 9)
- **Recessive Traits (Red eyes and Vestigial wings)**:
- wwll (total of 1)

### Conclusion
The F2 generation will predominantly consist of individuals with white eyes and long wings, and a smaller proportion with red eyes and vestigial wings.

### Final Answer
The F2 generation produced will be mostly white-eyed with long wings and a few red-eyed with vestigial wings.

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