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A colour blind man marries a normal woma...

A colour blind man marries a normal woman whose father was colour blin . What percentage of children is exdpected to bel colour blind?

A

0.25

B

0.5

C

0.75

D

1

Text Solution

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The correct Answer is:
To determine the percentage of children expected to be color blind from a color blind man and a normal woman whose father was color blind, we can follow these steps: ### Step 1: Understand the Genetics of Color Blindness Color blindness is a sex-linked trait, specifically linked to the X chromosome. Males have one X and one Y chromosome (XY), while females have two X chromosomes (XX). For a male to be color blind, he must inherit the color blind allele on his single X chromosome. A female must inherit two copies of the color blind allele (one from each parent) to be color blind. ### Step 2: Determine the Genotypes of the Parents - The color blind man has the genotype X^cY (where X^c represents the X chromosome with the color blind allele). - The normal woman has a normal X chromosome from her mother and a color blind X chromosome from her father. Therefore, her genotype is X^cX (she is a carrier). ### Step 3: Set Up a Punnett Square We can set up a Punnett square to determine the possible genotypes of their children: | | X^c (from father) | Y (from father) | |---------|-------------------|------------------| | X^c (from mother) | X^cX^c (color blind female) | X^cY (normal male) | | X (from mother) | XX (normal female) | XY (normal male) | ### Step 4: Analyze the Results From the Punnett square, we can see the possible genotypes of the children: 1. X^cX^c (color blind female) 2. X^cY (normal male) 3. XX (normal female) 4. XY (normal male) ### Step 5: Calculate the Percentage of Color Blind Children From the results: - 1 out of 4 children (X^cX^c) will be color blind. - Therefore, the percentage of children expected to be color blind is (1/4) * 100 = 25%. ### Conclusion The expected percentage of children who will be color blind is 25%. ---
To determine the percentage of children expected to be color blind from a color blind man and a normal woman whose father was color blind, we can follow these steps: ### Step 1: Understand the Genetics of Color Blindness Color blindness is a sex-linked trait, specifically linked to the X chromosome. Males have one X and one Y chromosome (XY), while females have two X chromosomes (XX). For a male to be color blind, he must inherit the color blind allele on his single X chromosome. A female must inherit two copies of the color blind allele (one from each parent) to be color blind. ### Step 2: Determine the Genotypes of the Parents - The color blind man has the genotype X^cY (where X^c represents the X chromosome with the color blind allele). - The normal woman has a normal X chromosome from her mother and a color blind X chromosome from her father. Therefore, her genotype is X^cX (she is a carrier). ...
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