Presence of recessive trait is 16% .The frequency of dominant allele in population is

Options

A. 0.6
B. 0.32
C. 0.84
D. 0.92

Explanation

To find the frequency of the dominant allele in the population, we can use the Hardy-Weinberg principle. Here’s a step-by-step solution:

### Step 1: Understand the given information
The problem states that the presence of the recessive trait is 16%. This means that the frequency of the recessive phenotype (which is represented by \( q^2 \)) is 0.16.

### Step 2: Calculate the frequency of the recessive allele (q)
Since \( q^2 = 0.16 \), we can find \( q \) by taking the square root of 0.16:
\[ q = \sqrt{0.16} = 0.4 \]

### Step 3: Use the Hardy-Weinberg equation
According to the Hardy-Weinberg principle, the sum of the frequencies of the dominant allele (\( p \)) and the recessive allele (\( q \)) is equal to 1:
\[ p + q = 1 \]

### Step 4: Solve for the frequency of the dominant allele (p)
Now that we know \( q = 0.4 \), we can substitute this value into the equation:
\[ p + 0.4 = 1 \]
Now, solving for \( p \):
\[ p = 1 - 0.4 = 0.6 \]

### Step 5: Conclusion
The frequency of the dominant allele in the population is \( 0.6 \) or 60%.

### Final Answer
The frequency of the dominant allele in the population is **0.6**.

---