If haemophilic female survives and marries a normal male , the theroetical ratio of their offspring regrding haimophilia will be

Options

A. All offspring haemophilc
B. All girls haemophilic
C. All sons haemophilic
D. 50% of sons and 50% daughters haemophilic .

Answer

To solve the problem regarding the inheritance of hemophilia when a hemophilic female marries a normal male, we need to understand the genetic basis of hemophilia, which is an X-linked recessive disorder. Here’s a step-by-step breakdown of the solution:

### Step 1: Understand the Genotypes
- A hemophilic female has the genotype **X^H X^H** (where X^H represents the hemophilic allele).
- A normal male has the genotype **X Y** (where X is the normal allele and Y is the male sex chromosome).

### Step 2: Determine the Gametes
- The hemophilic female can only produce gametes with the **X^H** chromosome.
- The normal male can produce two types of gametes: **X** (normal) and **Y** (male).

### Step 3: Set Up a Punnett Square
- We will set up a Punnett square to determine the possible genotypes of the offspring:

| | X (from male) | Y (from male) |
|---------|----------------|----------------|
| X^H (from female) | X^H X (carrier female) | X^H Y (hemophilic male) |
| X^H (from female) | X^H X (carrier female) | X^H Y (hemophilic male) |

### Step 4: Analyze the Offspring
- From the Punnett square, we can see the possible genotypes of the offspring:
- **50%** will be **X^H X** (carrier females)
- **50%** will be **X^H Y** (hemophilic males)

### Step 5: Conclusion
- The theoretical ratio of their offspring regarding hemophilia will be:
- **50% of sons will be hemophilic** (X^H Y)
- **100% of daughters will be carriers** (X^H X)

### Final Answer
Thus, the correct answer is **50% of sons and 50% of daughters hemophilic** is incorrect; instead, **all sons will be hemophilic** and **all daughters will be carriers**.