Hamemophilic carrier female marries a normal man .Her progeny will be

Options

A. All daughters will have hamemophilia
B. All sons will have hamemophilia
C. 560% doudghters will have haemophilia
D. 50% sons will have lhaemohphilia .

Answer

To solve the problem of a hemophilic carrier female marrying a normal man and determining the potential progeny, we can follow these steps:

### Step-by-Step Solution

1. **Identify the Genotypes**:
- The hemophilic carrier female has the genotype **X^H X** (where X^H represents the hemophilia allele and X represents the normal allele).
- The normal male has the genotype **X Y**.

2. **Determine the Gametes**:
- The female can produce two types of gametes: **X^H** and **X**.
- The male can produce two types of gametes: **X** and **Y**.

3. **Create a Punnett Square**:
- Set up a Punnett square to determine the possible combinations of the gametes from each parent.
- The rows will represent the female's gametes and the columns will represent the male's gametes.

```
X Y
----------------
X^H | X^H X | X^H Y |
----------------
X | X X | X Y |
```

4. **Analyze the Offspring**:
- From the Punnett square, we can identify the potential genotypes of the offspring:
- **X^H X** (female carrier)
- **X^H Y** (male with hemophilia)
- **X X** (normal female)
- **X Y** (normal male)

5. **Determine the Phenotypes**:
- The phenotypes based on the genotypes are:
- **X^H X**: Carrier female (not affected)
- **X^H Y**: Affected male (hemophilia)
- **X X**: Normal female
- **X Y**: Normal male

6. **Calculate the Ratios**:
- The offspring can be categorized as follows:
- 50% females (1 carrier, 1 normal)
- 50% males (1 affected, 1 normal)

### Conclusion
- The progeny will consist of:
- 50% daughters (1 carrier, 1 normal)
- 50% sons (1 hemophilic, 1 normal)

Thus, the correct answer is that **50% of the sons will have hemophilia**.