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A color blind male (XY) marries a carrie...

A color blind male (XY) marries a carrier female (XX) possible genotype of daughters will be
(a) X X only
(b) X X only
(c) X X and X X
(d) X X and X X

A

Xc Xconly

B

X C XC only

C

XC X Cand X cXc

D

XC Xc and X cXc

Text Solution

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The correct Answer is:
To solve the question about the possible genotypes of daughters from a colorblind male (XY) and a carrier female (XX), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Genotypes of the Parents**: - The colorblind male has the genotype **X^cY**, where **X^c** represents the X chromosome with the colorblind allele. - The carrier female has the genotype **XX**, where one X chromosome is normal (X) and the other is affected (X^c). Thus, her genotype can be represented as **X^cX**. 2. **Determine the Possible Alleles for Daughters**: - Daughters inherit one X chromosome from their father and one X chromosome from their mother. - From the father (colorblind male), the only X chromosome he can pass on is **X^c** (the colorblind allele). - From the mother (carrier female), she can pass on either **X** (normal) or **X^c** (colorblind). 3. **Combine the Alleles to Determine Daughters' Genotypes**: - The possible combinations of alleles for the daughters are: - From father: **X^c** (colorblind) - From mother: **X** (normal) → This results in the genotype **X^cX** (carrier daughter). - From mother: **X^c** (colorblind) → This results in the genotype **X^cX^c** (colorblind daughter). 4. **Conclusion**: - Therefore, the possible genotypes for the daughters are: - **X^cX** (carrier) - **X^cX^c** (colorblind) - Hence, the daughters can be either colorblind or carriers. 5. **Select the Correct Option**: - Based on the combinations, the correct answer is that the daughters can have genotypes **X^cX** and **X^cX^c**. ### Answer: The possible genotypes of the daughters will be (d) **X^cX and X^cX^c**. ---
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