Home
Class 7
CHEMISTRY
Razia conducted an experiment in the fie...

Razia conducted an experiment in the field related to the rate of percolation. She observed that it took 40 min for 200 mL of water to percolate through the soil sample. Calculate the rate of percolation.

Text Solution

AI Generated Solution

To calculate the rate of percolation, we can follow these steps: ### Step 1: Identify the amount of water percolated Razia observed that 200 mL of water was percolated through the soil sample. **Hint:** Look for the total volume of water used in the experiment. ### Step 2: Identify the time taken for percolation ...
Promotional Banner

Topper's Solved these Questions

  • SOIL

    NCERT|Exercise Exercise |8 Videos

  • PHYSICAL AND CHEMICAL CHANGES

    NCERT|Exercise EXERCISE |23 Videos

  • WATER : A PRECIOUS RESOURCE

    NCERT|Exercise EXERCISE (Fill in the blanks)|4 Videos

Similar Questions

Explore conceptually related problems

Percolation of soil water to water table occurs through

A 0.60 kg sample of water and a sample of ice are placed in two compartmetnts A and B separated by a conducting wall, in a thermally insulated container. The rate of heat transfer from the water to the ice through the conducting wall is constant P, until thermal equilibrium is reached. The temperature T of the liquid water and the ice are given in graph as functions of time t. Temperature of the compartments remain homogeneous during whole heat transfer process. Given specific heat of ice =2100 J//kg-K , specific heat of water =4200 J//kg-K , and latent heat of fusion of ice =3.3xx10^5 J//kg .

A 0.60 kg sample of water and a sample of ice are placed in two compartmetnts A and B separated by a conducting wall, in a thermally insulated container. The rate of heat transfer from the water to the ice through the conducting wall is constant P, until thermal equilibrium is reached. The temperature T of the liquid water and the ice are given in graph as functions of time t. Temperature of the compartments remain homogeneous during whole heat transfer process. Given specific heat of ice =2100 J//kg-K , specific heat of water =4200 J//kg-K , and latent heat of fusion of ice =3.3xx10^5 J//kg . Initial mass of the ice in the container equal to

A 0.60 kg sample of water and a sample of ice are placed in two compartmetnts A and B separated by a conducting wall, in a thermally insulated container. The rate of heat transfer from the water to the ice through the conducting wall is constant P, until thermal equilibrium is reached. The temperature T of the liquid water and the ice are given in graph as functions of time t. Temperature of the compartments remain homogeneous during whole heat transfer process. Given specific heat of ice =2100 J//kg-K , specific heat of water =4200 J//kg-K , and latent heat of fusion of ice =3.3xx10^5 J//kg . The mass of the ice formed due to conversion from the water till thermal equilibrium is reached is equal to

Water flows through a capillary tube of radius r and length l at a rate of 40 mL per second, when connected to a pressure difference of h cm of water. Another tube of the same length but radius r//2 is conncected in series with this tube and the combination is connected to the same pressure head. Calculate the pressure difference across each tube and the rate of flow of water through the combination.

Two vessels A and B of different materials but having identical shape, size and wall-thickness are filled with ice and kep at the same plane. Ice melts at the rate of 100 g min^(-1) and 150 g min^(-1) in A and B respectively. Assuming that heat enters the vessels through the walls only, calculate the ratio of thermal conductivity of their materials.

A pitcher with 1-mm thick porous walls contain 10kg of water. ,Water comes to its outer surface and evaporates at the rate of 0.1gs^(-1) . The surface area of the pitcher (one side) =200cm^(2) . The room temperature =42^(@)C , latent heat of vaporization =2.27xx10^(6)Jkg^(-1) , and the thermal conductivity of the porous walls =0.80js^(-1)m^(-1) ^(@)C^(-1) . Calculate the temperature of water in the pitcher when it attains a constant value.

A flat bottomed metal tank filled with water is dragged along a horizontal floor at the rate of 20 m//s The tank is of mass 100 kg and contains 900 kg of water and all the heat produced in the dragging is conducted to the water through the bottom plate of the tank. If the bottom plate has an effective area of conduction 1m^(2) and thickness 5 cm and the temperature of water in the tank remains constant at 50^(@) C, calculate the temperature of the bottom surface of the tank. Given the coefficient of friction between the tank and the floor is 0.5 and K for the material of the tank is 100 J//m sec K.