दिए गए परिपथ आरेख में, निवेश वोल्टता `(V_i) 20 V, V_(BE)` तथा `V_CE) = 0` है। `I_B, I_C `और `beta` के मान होंगे

Options

A. `I_B = 20 mu A, I_C = 5 mA , beta = 250`
B. `I_B = 25 mu A, I_C = 5 mA , beta = 200`
C. `I_B = 40 mu A, I_C = 10 mA , beta = 250`
D. `I_B = 40 mu A, I_C = 5 mA , beta = 125`

Answer

D

Explanation

प्रश्न से `V_(BE) = 0, V_t = 20 V`
`V_(CE) = 0`
`V_b = 0`
`I_B = ? , I_C = ?, beta = ?`

`I_C = ((20 - 0))/(4 xx 10^(3)) = 5 xx 10^(-3) = 5mA`
`V_i = V_(BE) = I_BR_B`
या ,`V_i = 0 + I_B R_B`
`implies 20 = I_B xx 500 xx 10^3`
`implies I_B = (20)/(500 xx 10^3) = 40 mu A`
`beta = (I_C)/(I_b) = (25 xx 10^(-3))/(40 xx 10^(-6)) = 125 `