A stone thrown vertically upwards with initaial velocity u reaches a height 'h' before coming down.Show that the time takes to go up is same as time taken to come down

A stone thrown vertically upwards with initial velocity u reaches a height h before coming down. Show that the time taken by it to go up is the same as the time taken to come down.

A stone is thrown vertically upwards with initial velocity of 14 m s^-1 . The maximum height it will reach is [g= 9.8 m s^-2]

A stone is thrown vertically upwards with initial velocity of 14 m s^-1 . The maximum height it will reach is [g = 9.8 m s^-2]

A stone is thorwn vertically upwards with initial velocity of 40m//s . Taking g=10m//s^2 find the maximum height and total distance covered by stone

A stone is thrown vertically upward with a velocity of 30 m//s . How high will it rise? After how much time will it return to ground ? [Take g = 10 m//s^2]

A tennis ball is thrown up and reaches a height of 4.05 m before coming down. What was its initial velocity? How much total time will it take to come down? Assume g=10m//s^(2)

A ball is thrown vertically upwards with a velocity of 49 m//s . Calulate (i) The maximum height to which it rises, (ii) the total time it takes to return to the surface of the earth.

A tennis ball is thrownb up and reahces a height of 4.05 m before coming down.What was its initial velocity? How much total time will it take to come down? Assumeg= 10m//s^2

i. Will the velocity of a stone thrown vertically upwards remian constant or will it change with time? How will it change? ii. Why doesn't the stone move up all the time? Why does it fall down after reaching a certain height? iii. What does its maximum height depend on?

An object is thrown vertically upwards and rises to a height of 10 m. Calculate (i) the velocity with which the object was thrown upwards and (ii) the time taken by the object to reach the highest point.