Find the gravitational potential energy of a body of mass 10 kg when it is at a height of 6400 km from the earth's surface. [M (earth) = 6xx 10^24 kg, R(earth) =6400 km]

Solve the following examples / numerical problems: Find the gravitational potential energy of a body of mass 10 kg when it is on the earth's surface. [M_(earth) = 6 xx10^24 kg , R_(earth) = 6.4 xx10^6m, G= 6.67 xx 10^-11 N-m^2/kg^2]

Find the gravitational potential energy of a body of mass 200 kg on the earth's surface . [M (earth) = 6xx 10^24 kg, R(earth) =6400 km]

Calculate the speed of a satellite in an orbit at a height of 1000 km from the Earth's surface. M_E = 6 xx 10^24 kg R_E = 6.4 10^6 m

Find the change in the gravitational potential energy when a body of mass m is raised to a height nR above the surface of the earth. (Here, R is the radius of the earth)

What is the gravitational potential due to the Earth at a point which is at a height of 2RE above the surface of the Earth, Mass of the Earth is 6xx10^24 kg, radius of the Earth = 6400 km and G = 6.67xx10^(-11) Nm^2 kg^(-2) .

Answer the following questions : Compare the gravitational force on a body of mass 1 kg due to the earth with the force on the same body due to another body of mass 1 kg at a distance of 1m from the first body. (Mass of the earth = 6xx10^24 kg, radius of the earth= 6400 km)

Derive an expression for critical velocity of satellite. Calculate the acceleration due to gravity at a height of 300 km from the surface of the earth. M = 6xx10^24kg R = 6400 km.

What will be the change in potential energy of a body of mass m when it is raised from height R_E above the Earth’s surface to 5/2 R_E above the Earth’s surface? R_E and M_E are the radius and mass of the Earth respectively

If a body of mass 10 kg is taken to the centre of the earth, its weight will be

Calculate the acceleration due to gravity at a height of 300 km from the surface of the Earth