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Three fractions, x, y and z, are such th...

Three fractions, x, y and z, are such that x > y > z. When the smallest of them is divided by the greatest, the result is `9/16`, which exceeds y by 0.0625. If `x +y+z=1 13/24` , then the value of x + z is:

A

`7/8`

B

`7/6`

C

`25/24`

D

1

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Three fractions, x,y and z, are such that x succ y succ z . When the smallest of them is divided by the greatest, the result is 9/16 , which exceeds y by 0.0625. If x+y+z =1 13/24 , then the value of x+z is : तीन भिन्न x, y और z इस प्रकार है कि x succ y succ z है | जब इनमें से सबसे छोटे को सबसे बड़े से विभाजित किया जाता है, तो परिणाम 9/16 आता है जो y से 0.0625 अधिक है | यदि x+y+z =1 13/24 है, तो x+z का मान ज्ञात करें |

If x, y, z are in H.P., then the value of (x+y)/(y-x)+(y+z)/(y-z) is

If x, y and z are three integers such that x + y = 8, y + z = 13 and z + x =17, then the value of (x^2)/(yz) is :

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