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If 5sin θ – 4cos θ = 0, 0^circ lt θ lt 9...

If `5sin θ – 4cos θ = 0, `0^circ lt θ lt 90^circ`, then the value of `(5sinθ− 2cosθ)/ (5 sin θ + 3cosθ)` is: यदि `5sin θ – 4cos θ = 0, `0^circ lt θ lt 90^circ`है, तो `(5sinθ− 2cosθ)/ (5 sin θ + 3cosθ)` का मान है:

A

`3/7`

B

`2/7`

C

`5/8`

D

`3/8`

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