Recommended Questions
- 17/7, 20/7, 23/7 എന്ന സമാന്തര ശ്രേണിയുടെ ബീജഗണിതരൂപം എഴുതുക.
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- 3/7 xx 7/17
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- |["sin"23^(@), -"sin"7^(@)], ["cos"23^(@), "cos"7^(@)]|=?
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- (3)/(7)+x=(17)/(7)
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- {:(5,6,3),(25,42,21),((2)/(7),(10)/(17),(20)/(?)):}
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- 17+7/7^2 का वर्ग है-
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- Solve the equation. 3/7 + x = 17/7
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- 3/7+x=17/7
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- सरल कीजिए - (23+7)-[-19+16+{26-(14-overline(17-2))}]
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