Solve: `(1/2)^(log^(10a^2))+2>3/(2^((log)_(10)(-a)))`

Solve : (1)/(log_(x)10)+2=(2)/(log_(0.5)(10))

Solve (x^(log_(10)3))^(2) - (3^(log_(10)x)) - 2 = 0 .

In a binomial distribution B(n , p=1/4) , if the probability of at least one success is greater than or equal to 9/(10) , then n is greater than (1) 1/((log)_(10)^4-(log)_(10)^3) (2) 1/((log)_(10)^4+(log)_(10)^3) (3) 9/((log)_(10)^4-(log)_(10)^3) (4) 4/((log)_(10)^4-(log)_(10)^3)

Solve for: x :(2x)^((log)_b2)=(3x)^((log)_b3) .

Solve : (iv) x^(log_(2)a)+a^(log_(2)x)=2a^(2) .

Solve |x-1|^((log_(10) x)^2-log_(10) x^2=|x-1|^3

Find the domain of the function : f(x)=sqrt((log)_(10){((log)_(10)x)/(2(3-(log)_(10)x)}}

Solve: 1/4x^(los_2sqrt(x))=(2. x^((log)_2x)1/4)dot

Solve : (iv) log_(10)x - log_(10)sqrt(x) = 2/(log_(10)x)

Solve: 27^(log_(3)root(3)(x^(2)-3x+1) )=(log_(2)(x-1))/(|log_(2)(x-1)|) .