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The perimeter of a triangle ABC is saix ...

The perimeter of a triangle ABC is saix times the arithmetic mean of the sines of its angles. If the side `ai s1` then find angle `Adot`

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Here,` a = 1`
It is given that,
`a+b+c = 6((sinA+sinB+sinC)/3)`
As `a = 2RsinA, b = 2RsinB and c = 2RsinC`
`=>2R(sinA+SinB+sinC) = 2(sinA+sinB+sinC)`
`=>R = 1`
Now, ` a = 2RsinA`
`1 = 2(1)sinA`
...
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