The general solution of the equation `8cosxcos2xcos4x=(sin6x)/(sin x)` is `x=((npi)/7)+(pi/(21)),AAn in Z` `x=((2pi)/7)+(pi/(14)),AAn in Z` `x=((npi)/7)+(pi/(14)),AAn in Z` `x=(npi)+(pi/(14)),AAn in Z`

Explanation

`4(2sinxcosx)cos2xcos4x=sin6x`

`4sin2xcos2xcos4x=sin6x`

`2(2sinxcos2x)cos4x=sin6x`

`2sin4xcos4x=sin6x`

`sin8x-sin6x=0`

`2cos((8x+6x)/2)*sin((8x-6x)/2)=0`

`2cos7xsinx=0`

`cos7x=0`

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