Solve the equation `sinx+cosx=1`

Solve the equation 2sinx+cosy=2 for the value of xa n dydot

alpha is a root of the equation (2sinx-cosx)(1+cosx)=sin^2x beta is a root of the equation 3cos^2x-10cosx+3=0 and gamma is a root of the equation 1-sin2x=cosx-sinx where 0 le alpha, beta, gamma le pi//2 Answer the following question on above passage: sin(alpha-beta)

alpha is a root of the equation (2sinx-cosx)(1+cosx)=sin^2x beta is a root of the equation 3cos^2x-10cosx+3=0 and gamma is a root of the equation 1-sin2x=cosx-sinx where 0 le alpha, beta, gamma le pi//2 Answer the following question on above passage: sinalpha+sinbeta+singamma can be equal

The number of real solutions of the equation (sinx-x)(cosx-x^(2))=0 is

The number of real solutions of the equation (sinx-x)(cosx-x^2)=0 is

Solve the equation (dy)/(dx)+ycotx=sinx

Solve the equation (sqrt(3))/2sinx-cosx=cos^2x

The equation sqrt3sinx+cosx=4 has

The equation sqrt(3)sinx+cosx=4 has

The equation sinx(sinx+cosx)=k has real solutions, where k is a real number, Then