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If (sinx)/a=(cosx)/b=(tanx)/c=k , then b...

If `(sinx)/a=(cosx)/b=(tanx)/c=k ,` then `b c+1/(c k)+(a k)/(1+b k)` is equal to

A

`k(a+1/a)`

B

`1//k(a+1/a)`

C

`1/(k^2)`

D

`a/k`

Text Solution

Verified by Experts

`sinx/a=cosx/b=tanx/c=k`
`bc+1/(ek)+(ak)/(1+bk)`
`cosx/k*tanx/k+1/tanx+sinx/(1+cosx)`
`sinx/k^2+1/tanx+sinx/(1+cosx)`
`(ak)/k^2+(cos(1+cosx)+sin^2x)/(sinx(1+cosx)`
`a/k+1/sinx`
`a/k+1/(ak)`
`1/k[a+1/a]`.
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