If `1+sinx+sin^2x+sin^3x+oo` is equal to `4+2sqrt(3),0ltxltpi,` then `x`is equal to

Explanation

`1+sinx+sin^2x+sin^3x+...oo = 4+2sqrt3`

`=>1/(1-sinx) = 4+2sqrt3`

`=>1-sinx = 1/(4+2sqrt3)**(4-2sqrt3)/(4-2sqrt3)`

`=>1-sinx = (4-2sqrt3)/(16-12) = (4-2sqrt3)/4`

`=>1-sinx = 1-sqrt3/2`

`=>sinx = sqrt3/2`

`:. x = pi/3 or (2pi)/3.`