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One of the general solutions of 4sin^4x+...

One of the general solutions of `4sin^4x+cos^4x=1` is `npi+-alpha/2,alpha=cos^(-1)(1/5),AAn in Z` `npi+-alpha/2,alpha=cos^(-1)(3/5),AAn in Z` `npi+-alpha/2,alpha=cos^(-1)(1/3),AAn in Z` none of these

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CENGAGE PUBLICATION-TRIGONOMETRIC FUNCTIONS-All Questions
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