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If sin^2theta=(x^2+y^2+1)/(2x) , then x...

If `sin^2theta=(x^2+y^2+1)/(2x)` , then `x` must be `-3` (b) `-2` (c) `1` (d) none of these

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`sin^2theta=(x^2+y^2+1)/(2x)`
`(x^2+y^2+1)/(2x)=<1`
`x^2+y^2+1<=2x`
`x^2+y^2-2x+1<=0`
`(x-1)^2+y^2<=0`
`x-1=0,y=0`
`x=1,y=0`.
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