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If cos3x+sin(2x-(7pi)/6)=-2 , then show ...

If `cos3x+sin(2x-(7pi)/6)=-2` , then show that x is of the form π / 3(6n+1) .

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`cos3xx+sin(2x-7/5pi)=-2`
`1+cos3x+1+sin(3x-7/6pi)=0`
`2cos^2 3/2x+1+sin(3x-2/3pi-pi/2)=0`
`2cos^2(3/2x)+1-sin(pi/2-(-3x+2/3pi))=0`
`2cos^2(3/2x)+1-cos(2/3pi-2x)=0`
`2cos^2(3/2x)+2sin^2(pi/3-x)=0`
`cos3/2x=0,sin(pi/3-x)=0`
`3/2x=pi/2,3/2pi,5/2pi,7/2pi...`
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