Let `A B C` be a triangle such that `/_A C B=pi/6` and let `a` , `b` and `c` denote the lengths of the side opposite to `A , B` ,and `C` respectively. The value(s) of `x` for which `a=x^2+x+1,b=x^2-1,\and\ c=2x+1` is(are) `-(2+sqrt(3))` (b) `1+sqrt(3)` (c)`2+sqrt(3)` (d) `4sqrt(3)`

If the angle A ,Ba n dC of a triangle are in an arithmetic propression and if a , ba n dc denote the lengths of the sides opposite to A ,Ba n dC respectively, then the value of the expression a/csin2C+c/asin2A is (a) 1/2 (b) (sqrt(3))/2 (c) 1 (d) sqrt(3)

In a triangle DeltaXYZ, let a, b, and c be the length of the sides opposites to the angles X,Y and Z, respectively.If 1+cos2X-2cos2Y=2sinXsinY , then possible value(s) of a/b is (are)

The length of the chord of the parabola y^2=x which is bisected at the point (2, 1) is 2sqrt(3) (b) 4sqrt(3) (c) 3sqrt(2) (d) 2sqrt(5)

If tan^(-1)x+2cot^(-1)x=(2pi)/3, then x , is equal to (a) (sqrt(3)-1)/(sqrt(3)+1) (b) 3 (c) sqrt(3) (d) sqrt(2)

Consider a triangle A B C and let a , ba n dc denote the lengths of the sides opposite to vertices A , B ,a n dC , respectively. Suppose a=6,b=10 , and the area of triangle is 15sqrt(3)dot If /_A C B is obtuse and if r denotes the radius of the incircle of the triangle, then the value of r^2 is

Vertices of a variable acute angled triangle A B C lies on a fixed circle. Also, a ,b ,ca n dA ,B ,C are lengths of sides and angles of triangle A B C , respectively. If x_1, x_2a n dx_3 are distances of orthocenter from A ,Ba n dC , respectively, then the maximum value of ((dx_1)/(d a)+(dx_2)/(d b)+(dx_3)/(d c))+11 is a. -sqrt(3) b. 11-3sqrt(3) c. 11+6sqrt(3) d. 3sqrt(3)

The function f(x)=x(x+4)e^(-x//2) has its local maxima at x=adot Then (a) a=2sqrt(2) (b) a=1-sqrt(3) (c) a=-1+sqrt(3) (d) a=-4

Let f: R->R be given by f(x)=x^2-3 . Then, f^(-1) is given by (a)sqrt(x+3) (b) sqrt(x)+3 (c) x+sqrt(3) (d) none of these

If A(1,p^2),B(0,1) and C(p ,0) are the coordinates of three points, then the value of p for which the area of triangle A B C is the minimum is (a) 1/(sqrt(3)) (b) -1/(sqrt(3)) (c) 1/(sqrt(2)) (d) none of these

f(x)=(x-1)|(x-2)(x-3)|dot Then f decreases in (a) (2-1/(sqrt(3)),2) (b) (2,2+1/(sqrt(3))) (c) (2+1/(sqrt(3)),3) (d) (3,oo)