Let ABC be a triangle of area 24sq.units and PQR be the triangle formed by the mid-points of the sides triangle ABC. Then what is the area of triangle PQR.

Prove analytically that the area of a triangle is four times that of the triangle obtained by joining the mid - points of the sides of the given triangle .

ABC is an equilateral triangle. D and E are the mid-points of AB and AC. Then angleADE=

If in triangle ABC if acosA=bcosB then the triangle will be

Let PQR be a triangle of area Delta with a=2,b=7/2 and c=5/2 , where a,b and c are the lengths of the sides of the triangle opposite to the angles at P,Q and R respectively. Then ((2sinP-sin2P)/ (2sinP+sin2P)) equals

A triangle with equal sides has perimeter 9 cm. Then find the area of the triangle

In triangle ABC, If cos B= a/(2c) , then the triangle is-

Find the area of the triangle formed by joining the mid-points of the sides of the triangle whose vertices are (0, -1), (2, 1) and (0, 3). Find the ratio of this area to the area of the given triangle.

ABDE is a parallelogram. F is the mid-point of ED. If the area of the triangle ABD be 20 sq.cm, find the area of DeltaAEF .

Consider the parabola y^2 = 8x. Let Delta_1 be the area of the triangle formed by the end points of its latus rectum and the point P( 1/2 ,2) on the parabola and Delta_2 be the area of the triangle formed by drawing tangents at P and at the end points of latus rectum. Delta_1/Delta_2 is :

The areas of a square of sides x and a triangle of base x are equal, then the height of the triangle is