In ` A B C ,(cot (A/2)+cot(B/2))(asin^2(B/2)+bsin^2(A/2))=` (a) `cotC` (b) c`cotC` (c) `cot(C/2)` (d) c`cot(C/2)`

In any triangle prove that cot(A/2)+cot (B/2)+cot(C/2)=cot(A/2)cot(B/2)cot(C/2)

In Delta ABC, "cot"(A)/(2) + "cot" (B)/(2) + "cot" (C)/(2) is equal to

In any /_\ A B C , prove that (b^2-c^2)cotA+(c^2-a^2)cotB+(c^2-b^2)cotC=0

In triangle A B C , if |[1, 1, 1],[cot(A/2),cot(B/2),cot(C/2)],[tan(B/2)+tan(C/2),tan(C/2)+tan(A/2),tan(A/2) +tan(B/2)]| =0 then the triangle must be a. equilateral b. isosceles c. obtuse angled d. none of these

In triangle A B C ,a , b , c are the lengths of its sides and A , B ,C are the angles of triangle A B Cdot The correct relation is given by (a) (b-c)sin((B-C)/2)=acosA/2 (b) (b-c)cos(A/2)=asin((B-C)/2) (c) (b+c)sin((B+C)/2)=acosA/2 (d) (b-c)cos(A/2)=2asin(B+C)/2

Prove that in any /_\ABC . (b-c)cot(A/2)+(c-a)cot (B/2)+(a-b)cot (C/2)=0

(xii) (b+c-a)(cot 'B/2' + cot 'C/2') = 2a cot 'A/2

In A B C ,cotA/2+cotB/2+cotC/2 is equal to Delta/(r^2) (b) ((a+b+c)^2)/(a b c)2R (c) Delta/r (d) Delta/(R r)

If cosx-sinalphacotbetasinx=cosa , then the value of tan(x/2) is (a) -tan(alpha/2)cot(beta/2) (b) tan(alpha/2)tan(beta/2) (c) -cot((alphabeta)/2)tan(beta/2) (d) cot(alpha/2)cot(beta/2)

Prove that (b + c -a) (cot.(B)/(2) + cot.(C)/(2)) = 2a cot.(A)/(2)