In A B C , internal angle bisector of /...

In ` A B C ,` internal angle bisector of `/_A` meets side `B C` in `D .` `DE_|_A D` meets `A C` at `E and A B` at `F.` Then (a) `A E` is in `H.P.` of `b` and `c` (b) `A D=(2b c)/(b+c)cosA/2` (c) `E F=(4b c)/(b+c)sinA/2` (d) ` AEF` is isosceles

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In A B C , the bisector of the angle A meets the side BC at D andthe circumscribed circle at E. Prove that D E=(a^2secA/2)/(2(b+c))

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