Find the smallest positive root of the equation `sqrt(sin(1-x))=sqrt(cos"x")`

Explanation

`sqrt(sin(1-x)) = sqrtcosx`

`=>sin(1-x) = cosx`

`=>cos(pi/2-(1-x)) = cosx`

`=>pi/2-1+x = 2npi+-x`, where `n in Z.`

`=>x = (2npi-pi/2+1)/2`

As we have to find the smallest positive root of the equation,

it will come when `n = 2`.

`:. x = (4pi-pi/2 +1)/2`

...